MoreLinq
TakeEvery<(Of <(<'TSource>)>)> Method (source, step)
NamespacesMoreLinqMoreEnumerableTakeEvery<(Of <<'(TSource>)>>)(IEnumerable<(Of <<'(TSource>)>>), Int32)
Returns every N-th element of a source sequence.
Declaration Syntax
C#Visual BasicVisual C++
public static IEnumerable<TSource> TakeEvery<TSource>(
	this IEnumerable<TSource> source,
	int step
)
<ExtensionAttribute> _
Public Shared Function TakeEvery(Of TSource) ( _
	source As IEnumerable(Of TSource), _
	step As Integer _
) As IEnumerable(Of TSource)
public:
[ExtensionAttribute]
generic<typename TSource>
static IEnumerable<TSource>^ TakeEvery(
	IEnumerable<TSource>^ source, 
	int step
)
Generic Template Parameters
TSource
Type of the source sequence
Parameters
source (IEnumerable<(Of <(<'TSource>)>)>)
Source sequence
step (Int32)
Number of elements to bypass before returning the next element.
Return Value

[Missing <returns> documentation for "M:MoreLinq.MoreEnumerable.TakeEvery``1(System.Collections.Generic.IEnumerable{``0},System.Int32)"]

Usage Note
In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<(Of <(<'TSource>)>)>. When you use instance method syntax to call this method, omit the first parameter.
Remarks
This operator uses deferred execution and streams its results.
Examples
 Copy imageCopy
int[] numbers = { 1, 2, 3, 4, 5 };
IEnumerable<int> result = numbers.TakeEvery(2);
The result variable, when iterated over, will yield 1, 3 and 5, in turn.

Assembly: MoreLinq (Module: MoreLinq.dll) Version: 1.0.16006.0 (1.0.16006.1845)