ZipLongest Method (first, second, resultSelector)

Returns a projection of tuples, where each tuple contains the N-th element from each of the argument sequences.

Declaration Syntax

Visual Basic

Visual C++

public static IEnumerable<TResult> ZipLongest<TFirst, TSecond, TResult>(
	this IEnumerable<TFirst> first,
	IEnumerable<TSecond> second,
	Func<TFirst, TSecond, TResult> resultSelector
)

<ExtensionAttribute> _
Public Shared Function ZipLongest(Of TFirst, TSecond, TResult) ( _
	first As IEnumerable(Of TFirst), _
	second As IEnumerable(Of TSecond), _
	resultSelector As Func(Of TFirst, TSecond, TResult) _
) As IEnumerable(Of TResult)

public:
[ExtensionAttribute]
generic<typename TFirst, typename TSecond, typename TResult>
static IEnumerable<TResult>^ ZipLongest(
	IEnumerable<TFirst>^ first, 
	IEnumerable<TSecond>^ second, 
	Func<TFirst, TSecond, TResult>^ resultSelector
)

Generic Template Parameters

TFirst: Type of elements in first sequence
TSecond: Type of elements in second sequence
TResult: Type of elements in result sequence

Parameters

first (IEnumerable<(Of <(<'TFirst>)>)>): First sequence

second (IEnumerable<(Of <(<'TSecond>)>)>): Second sequence

resultSelector (Func<(Of <(<'TFirst, TSecond, TResult>)>)>): Function to apply to each pair of elements

Return Value

[Missing <returns> documentation for "M:MoreLinq.MoreEnumerable.ZipLongest``3(System.Collections.Generic.IEnumerable{``0},System.Collections.Generic.IEnumerable{``1},System.Func{``0,``1,``2})"]

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<(Of <(<'TFirst>)>)>. When you use instance method syntax to call this method, omit the first parameter.

Remarks

If the two input sequences are of different lengths then the result sequence will always be as long as the longer of the two input sequences. The default value of the shorter sequence element type is used for padding. This operator uses deferred execution and streams its results.

Examples

	Copy
int[] numbers = { 1, 2, 3 }; string[] letters = { "A", "B", "C", "D" }; var zipped = numbers.EquiZip(letters, (n, l) => n + l);

The zipped variable, when iterated over, will yield "1A", "2B", "3C", "0D" in turn.

Assembly: MoreLinq (Module: MoreLinq.dll) Version: 1.0.16006.0 (1.0.16006.1845)